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From | To | Subject | Date/Time | |||
Jeff Smith | Janis | Date Variable in Linux |
January 10, 2017 11:56 PM * |
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Hello Janis, I know that I can specify a DOY (Day of Year) variable in a bash file as "DOY=$(date +%j)". But, I would only want the variable to express the last two digits of DOY. So... 010 would be expressed as 10 and 165 would be expressed as 65, etc. I looking at grabbing a zipped file with a filename of filename.znn where "nn" is the DOY minus the first digit. Any thoughts? If I am making any sense. <g> Jeff --- SBBSecho 3.00-Linux * Origin: The OuijaBoard Too - Anoka, MN (1:282/1032) |
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